Matematika Sekolah Menengah Atas Jika:[tex]~~~~~~[/tex]a = √8[tex]~~~~~~[/tex]b = √18[tex]~~~~~~[/tex]c = √32MAKA:nilai 2a + 2b - c = ......silakan dicari^^​

pearlieboscoulv – March 08, 2023

Jika:
[tex]~~~~~~[/tex]a = √8
[tex]~~~~~~[/tex]b = √18
[tex]~~~~~~[/tex]c = √32


MAKA:

nilai 2a + 2b - c = ..


....

silakan dicari^^​

~ Akar

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Pembahasan :

Diketahui a = √8, b = √18, dan c = √32. Sedang yg ditanyakan adalah nilai dr 2a + 2b - c = ... ?

2a + 2b - c

[tex] = ( 2\sqrt{8} ) + (2 \sqrt{18} ) - \sqrt{32} [/tex]

[tex] = (4 \sqrt{2} ) +( 6 \sqrt{2} ) - 2 {}^{2} \sqrt{2} [/tex]

[tex] = 4 \sqrt{2} + 6 \sqrt{2} - 4 \sqrt{2} [/tex]

[tex] = (4 + 6 - 4) \sqrt{2} [/tex]

[tex] = 6 \sqrt{2} [/tex]

Kesimpulan :

Jadi, nilai dr 2a + 2b - c adalah 6√2

2a + 2b - C

2 × √8 + 2 × √18 - √32

2 × ( √4×2 ) + 2 × ( √9×2 ) - √16×2

2 ( 2√2 ) + 2 × ( 3√2 ) - 4√2

4√2 + 6√2 - 4√2

( 4 + 6 - 4 )√2

( 10 - 4 )√2

6√2

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